|
|
|
x
|
|
--»
|
|
P1
|
|
P2
|
|
F1
|
Yellow
|
|
green
|
|
all Yellow
|
|
|
|
|
|
|
|
|
|
|
|
|
x
|
|
--»
|
|
F1
|
|
F1
|
|
|
|
|
|
|
|
|
|
|
|
F2
|
|
(F2)
Yellow : green = 3 : 1
|
|
If there are
discrete heredity units
|
in pairs, than
not all F2
yellow
|
coloured seeds
are the same as
|
those from the
parental
|
generation. Some
will be -having
|
the dominant unit
for producing the
|
characteristic
yellow twice than-,
|
but others will
be as the yellow
|
seeds in the F1
generation which
|
have the dominant
yellow
|
producing unit
and the recessive
|
green one latent
present.
|
If this thesis is
correct, than again
|
it can be
demonstrated by the ratio
|
between the quantities
of yellow
|
and green seeds
to be found in the
|
offspring of
backcrosses of the F1
|
and F2
yellow seeds with the green
|
seeds of the
parental generation.
|
For these green
seeds have double
|
recessive
heredity units producing
|
the green
characteristic so that, if
|
the green colour
producing
|
heredity unit is
latent in those F1
|
and F2
yellow seeds, green seeds
|
will and must be
found in the
|
offspring of
these crosses in
|
quantities
corresponding to the
|
number of
possibilities for passing
|
on these discrete
heredity units.
|
|
So Mendel
executed hundreds of
|
these back
crosses and indeed
|
|
|
|
|
|
|
|
|
|
|
1/2 yellow
|
|
x
|
|
--»
|
|
F1
|
|
P2
|
|
|
|
|
|
|
|
|
|
|
1/2 green
|
-------------------------------------------
|
|
|
|
|
|
|
|
|
|
2/3
yellow
|
|
x
|
|
--»
|
|
F2
|
|
P2
|
|
|
|
|
|
|
|
|
|
|
1/3 green
|
|
the foreseen
ratio were found.
|
|