x  --»  
  P1    P2       F1
Yellow green all Yellow
   
 
 
x  --»
F1 F1  
 
      F2
        
(F2) Yellow : green = 3 : 1
       
 If there are discrete heredity units
 in pairs, than not all F2 yellow
 coloured seeds are the same as
 those from the parental
 generation. Some will be -having
 the dominant unit for producing the
 characteristic yellow twice than-,
 but others will be as the yellow
 seeds in the F1 generation which
 have the dominant yellow
 producing unit and the recessive
 green one latent present.
 If this thesis is correct, than again
 it can be demonstrated by the ratio
 between the quantities of yellow
 and green seeds to be found in the
 offspring of backcrosses of the F1
 and F2 yellow seeds with the green
 seeds of the parental generation.
 For these green seeds have double
 recessive heredity units producing
 the green characteristic so that, if 
 the green colour producing
 heredity unit is latent in those F1
 and F2 yellow seeds, green seeds
 will and must be found in the
 offspring of these crosses in
 quantities corresponding to the
 number of possibilities for passing
 on these discrete heredity units.
       
 So Mendel executed hundreds of
 these back crosses and indeed
          
  
1/2 yellow
x  --»
  F1    P2   
1/2 green
-------------------------------------------
  
2/3 yellow
x  --»
  F2    P2   
1/3 green
         
 the foreseen ratio were found.
         
   >>> 
      
      
  
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